Supercharged/Turbocharged The increase in air/fuel pressure above atmospheric pressure in the intake system caused by the action of a supercharger or turbocharger attached to an engine.

What adaptor do I need to hook my AEM FPR to my fuel rail?

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Old Aug 5, 2003 | 10:03 AM
  #1  
Craig Mack's Avatar
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What adaptor do I need to hook my AEM FPR to my fuel rail?

Well, my AEM FPR is here, and all my fittings for it (90 degree elbows, bolts, screws) came in yesterday. Well, the only thing I'm lacking is the adaptor peice needed to connect my fuel rail to the FPR. I PM'ed Sx7r and talked to SeximaGTR about it, but no info so far. Does anyone know where I can get this little adaptor peice?


BTW, Here is a pic of the type of FPR I have. The hole in the front that I circled has a black thing in it whereas mine is open and is threaded. There is nothing that came with my kit that would go in there. Any help is appriciated.

Old Aug 5, 2003 | 11:59 AM
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sent you a pm. that plug that you have circled is just a standard 1/8NPT gauge port.
Old Aug 5, 2003 | 02:08 PM
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Originally posted by sx7r
that plug that you have circled is just a standard 1/8NPT gauge port.
For what though?
Old Aug 5, 2003 | 02:28 PM
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oh yeah, craig... you can stick the sending unit for your guage there.
Old Aug 5, 2003 | 02:55 PM
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for a fuel pressure gauge.
Old Aug 5, 2003 | 04:14 PM
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Would it give me a more accurate reading if I switched it into there?
Old Aug 6, 2003 | 06:10 AM
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Originally posted by Craig Mack
Would it give me a more accurate reading if I switched it into there?
Not really. Fuel pressure should be pretty much the same anywhere in the circuit between the fuel pump and fpr. I don't think fuel flows fast enough for there to be a significant pressure drop through the circuit due to viscous drag. Plus the fuel is pretty near inviscid anyway.
Old Aug 6, 2003 | 09:37 AM
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Craig Mack's Avatar
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Originally posted by Stephen Max


Not really. Fuel pressure should be pretty much the same anywhere in the circuit between the fuel pump and fpr. I don't think fuel flows fast enough for there to be a significant pressure drop through the circuit due to viscous drag. Plus the fuel is pretty near inviscid anyway.
I see, thanks.
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