Ohm Question
Wiring the voice coils in parallel will give you 1 ohm, series will give you 4.
Originally Posted by Kikcaffine
How many ohms of resistence are made from 4 12's that are 2 ohms a piece, single voice coil?
Reading your initial question again, my answer was based on subs with dual voicecoil (dual 2ohms). With the dvc, you get 1 ohm (per sub) wiring each voice coil in parallel, and 4 ohms (per sub) in series.
To quickly answer your question, (4) 12' subs that is 2 ohms each (single voice coil) will not work with one amp because it will give the amp less than an ohm of load. Most amps aren't stable in <1ohm of load. The only time you can use all 4 of your subs is if you run a separate amp on each one. Or use only 1 sub which will drive your amp into 2 ohm load.
Look at these links for further info:
http://www.jlaudio.com/tutorials/dvc/index.html
http://www.jlaudio.com/tutorials/wir...dex.html#3svcp
Hope this helps.
To quickly answer your question, (4) 12' subs that is 2 ohms each (single voice coil) will not work with one amp because it will give the amp less than an ohm of load. Most amps aren't stable in <1ohm of load. The only time you can use all 4 of your subs is if you run a separate amp on each one. Or use only 1 sub which will drive your amp into 2 ohm load.
Look at these links for further info:
http://www.jlaudio.com/tutorials/dvc/index.html
http://www.jlaudio.com/tutorials/wir...dex.html#3svcp
Hope this helps.
Originally Posted by Kikcaffine
can most 1 ohm stable amps run 4 12's?
Yeah, it's fine... as long as your amp is that powerfull to push all four of them. You can wire them as following:
Sub A & B in parallel = 1 ohm load
Sub C & D in parallel = 1 ohm load
Connect these 2 loads in series, so that you get 2 ohms
That's what people usually do with 2 DVC subs.
Sub A & B in parallel = 1 ohm load
Sub C & D in parallel = 1 ohm load
Connect these 2 loads in series, so that you get 2 ohms
That's what people usually do with 2 DVC subs.
Originally Posted by 2DaMax
Reading your initial question again, my answer was based on subs with dual voicecoil (dual 2ohms). With the dvc, you get 1 ohm (per sub) wiring each voice coil in parallel, and 4 ohms (per sub) in series.
To quickly answer your question, (4) 12' subs that is 2 ohms each (single voice coil) will not work with one amp because it will give the amp less than an ohm of load. Most amps aren't stable in <1ohm of load. The only time you can use all 4 of your subs is if you run a separate amp on each one. Or use only 1 sub which will drive your amp into 2 ohm load.
Look at these links for further info:
http://www.jlaudio.com/tutorials/dvc/index.html
http://www.jlaudio.com/tutorials/wir...dex.html#3svcp
Hope this helps.
To quickly answer your question, (4) 12' subs that is 2 ohms each (single voice coil) will not work with one amp because it will give the amp less than an ohm of load. Most amps aren't stable in <1ohm of load. The only time you can use all 4 of your subs is if you run a separate amp on each one. Or use only 1 sub which will drive your amp into 2 ohm load.
Look at these links for further info:
http://www.jlaudio.com/tutorials/dvc/index.html
http://www.jlaudio.com/tutorials/wir...dex.html#3svcp
Hope this helps.
The amp could also work if it was a 2 channel..2 Ohm stereo capable.
--Don
Hmmm....never thought of it that way! I never had that many subs to wire together and give the least amount of loads.
Kikcaffine, how are you going to fit (4) 12" in the trunk?
Kikcaffine, how are you going to fit (4) 12" in the trunk?
Originally Posted by krasavchic
Yeah, it's fine... as long as your amp is that powerfull to push all four of them. You can wire them as following:
Sub A & B in parallel = 1 ohm load
Sub C & D in parallel = 1 ohm load
Connect these 2 loads in series, so that you get 2 ohms
That's what people usually do with 2 DVC subs.
Sub A & B in parallel = 1 ohm load
Sub C & D in parallel = 1 ohm load
Connect these 2 loads in series, so that you get 2 ohms
That's what people usually do with 2 DVC subs.
Interesting......all 4 subs are going to be inside the box firing outward, from its own chambers? If so, that's going to be a pretty big box...no?
Originally Posted by Kikcaffine
2 in the back, and one on each side
the back 2 are in, the side two will prove to be difficult though
the back 2 are in, the side two will prove to be difficult though
I found this link which should be very useful, it has many tools. Enjoy!
http://www.the12volt.com/caraudio/boxcalcs.asp
http://www.the12volt.com/caraudio/boxcalcs.asp
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