if i wire a speaker thats 8ohms parrallell with a tweeter thats 4ohm i get a 2.66 ohm ,right,correct me if im wrong.
now if my amp puts out 100 watts @2ohm , how many watts go to the speaker and tweeter

 

general rule is that when u wire anything in parallel...ur total resistance(impedence) is less then ur smallest value...here is the equation: [1/{(1/r1)+(1/r2)+(1/rx)}]=total resistance when wired parallel...

 

so .... is 2.66 ohm right or wrong and how many watts will the speaker n tweet get

 

do the math son...i gave u the formula...hehe...j/p...yeah it's rite...and since it is wired in parallel...according to ohms law...the one with lower resistance (impedence) should get more of the power...as a matter of fact the 4 ohm should get twice the power of the 8 ohm...correct me if i'm wrong someone...it's been a while...ohm's law is kinda shaky in my head rite now...

 

If this was a strictly resistive circuit yeah an 8 ohm and 4 ohm in parallel would be 2.66 ohms BUT this is a reactive circuit meaning AC
and different frequencies.

No one in their right mind would wire a 8ohm speaker with a 4 ohm tweeter without a crossover, even if it was only a 6db cap. where your amp would see more of the 8 ohms below the xover freq and 4 ohms above.

BTW
Watts = I (current)^2 x R (resistance) or
Watts = I (current) x E (Voltage)

 

No one in their right mind would wire a 8ohm speaker with a 4 ohm tweeter without a crossover, even if it was only a 6db cap.

I'll second that. Don't worry about ohms law untill you have something that can be hooked up. Tweeters are generally more efficient than mids and woofers so usually have a resistor somewhere to balance the output of the larger driver. As it is your tweeter will blow about the same time you get the volume **** to the point where you can just hear the woofer.