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Powerloss due to rotational weight and stuff

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Old Sep 21, 2004 | 05:46 PM
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SLC I30t's Avatar
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Powerloss due to rotational weight and stuff

Ok I have a question.

How much power am I losing by inceasing my wheel weight by 4lbs per wheel?

My new rims are lighter but the rubber is heavier, so my OEM wheel set up is 32lbs with rubber and the OZ rim with rubber is 36lbs. Is there any way to figure out what kind of powerloss I'm experiencing.
Old Sep 22, 2004 | 01:46 PM
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another thing to factor in is the distance from the hub the weight is. Its easyer for a mass closer to the center to spin than one that is further away from the axis. ie, bigger wheels are that much worse compared to a smaller wheel of the same weight


i think
Old Sep 23, 2004 | 10:01 AM
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there is a mathematical equation to figure out the power loss.
Old Sep 23, 2004 | 11:24 PM
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Is this what you're looking for?

Formulas for tire size & their effect

effective ratio = (old tire diameter / new tire diameter) x original ratio

actual mph = (new tire diameter / old tire diameter) x actual mph

But I think this is what you are looking for, check the bottom of the page:

http://www.pumaracing.co.uk/flywheel.htm
Old Sep 28, 2004 | 12:44 PM
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ummm errr I'll have to work that one out.

I just remember an equation to figure it out... it came out to something like 1lb of rotational weight equaled like 90lbs of unsprung weight. something wierd like that...
Old Sep 28, 2004 | 04:34 PM
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i believe it was for every 1lb it was 8lb's of "dead" weight. so if it is a 4lbs difference in each wheel, it is equal to 128lbs of dead weight.
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