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How would I figure out my average speed in the 1/4...

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Old 11-23-2000, 07:25 PM
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Add my 1/8 mile speed and my 1/4 mile speed together than devide that by two?? So I run 77+96=173 than devide that by two is 86.5 I suck *** at math so would this be right?
Or do you have to know your speed at every foot or something crazy like that..
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Old 11-23-2000, 07:29 PM
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Old 11-23-2000, 07:31 PM
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Well, if you had a plot of your speed vs distance, you could then find the area under the curve and divide by the distance. Or, if you had some data points of speed vs distance at various points along the track, you could fit a function through those points, integrate the function over the distance, and then divide by the total distance.

Well, you asked...
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Old 11-23-2000, 07:57 PM
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uh

why would you want to add your 1/8 and your 1/4 to get an average 1/4. If youve only done one 1/4 run, your average is the total time it took you to do 1/4. Youd need more data to get an average (at least 2 sets).
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Old 11-23-2000, 09:57 PM
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Originally posted by deathwish

Well, if you had a plot of your speed vs distance, you could then find the area under the curve and divide by the distance. Or, if you had some data points of speed vs distance at various points along the track, you could fit a function through those points, integrate the function over the distance, and then divide by the total distance.

Well, you asked...
joy....statistics...glad i never have to take those courses again
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Old 11-24-2000, 12:08 AM
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Originally posted by Chris91SE
Originally posted by deathwish

Well, if you had a plot of your speed vs distance, you could then find the area under the curve and divide by the distance. Or, if you had some data points of speed vs distance at various points along the track, you could fit a function through those points, integrate the function over the distance, and then divide by the total distance.

Well, you asked...
joy....statistics...glad i never have to take those courses again
Not stats Chris... calculus.
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Old 11-24-2000, 09:19 AM
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Average speed, for the 1/4 (or any distance, doesn't matter) is Vf - Vo / 2 (final velocity - initial velocity. You only need calculus for calculating instantanious velocities.
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Old 11-24-2000, 09:58 AM
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damn you!

I was just about to post that equation. Good ol physics.
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Old 11-24-2000, 10:27 AM
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Originally posted by brubenstein
Average speed, for the 1/4 (or any distance, doesn't matter) is Vf - Vo / 2 (final velocity - initial velocity. You only need calculus for calculating instantanious velocities.
No... That would be the average of your starting and ending speed, not your average speed. That would be the solution to the integral of velocity over distance if and only if you have constant acceleration, which we don't. Besides, Vf-Vo/2 is calculus, it's calculating an integral for a specialized circumstance.
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