please refer to this thread, thanks

http://forums.maxima.org/showthread....222#post330222

if that doesnt work, its in the 4th gen forum called "interior lighting question." please help me out, im planning on doing it tomorrow if possible, thanks

 

A resistor would work but you need to know the resistence of the light in order to calculate the value of resistor to use. But then again, the resistor will be generating heat, not sure how much, but some nonethless. Another option would be to incorporate a voltage regulating circuit... I'll try to draw up a diagram with required part, if I have time.

 

thanks a bunch

 

Sorry, I forgot about this.
Anyways, um, well the cheapest way to go would be adding a series resistor.

If you know the spec. of the new bulb, then you can calculate what the value of the resistor needs to be.
I calculated the formula for your 9V bulb:

R = (V^2)/3P V=9 Volts
P = bulb power in Watts.

This formula is specific only for a 9V bulb in a 12V circuit without any other loads.

The resistor you select should be a little more than
the value of R calculated above and that's just to prolong the life of the bulb. Not sure how much heat the resistor will give off though.

There are other methods for this circuit... diode, voltage regulator.. but these are all overkills for your application.