is this right...q on some things
08-26-2001, 04:45 PM
#1
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Join Date: Aug 2001
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amp says (rms)75x2 into 4ohms ,then 150x2 into 2 ohms.I have 2 4ohm subs ,now when i hook it up by bridging 2 channels do my subs fall into 150x2 at 2ohms power rating
and when people say run subs or speakers parallel ,does that mean normally like one speaker per channel, not bridging channels
and when people say run subs or speakers parallel ,does that mean normally like one speaker per channel, not bridging channels
08-26-2001, 09:00 PM
#2
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If you bridge two 4 ohm subs to a pair of amp channels which are also bridged it will be a 1 ohm load at the amp. You see (4/2)/2.
Remember the old Christmas tree lights? When one bulb burnt out the whole string of lights would turn off. They were wired in series. A positive came from the wall outlet to the first bulb, from that negative terminal it ran to the next bulbs positive, from that bulbs negative to the next bulbs positive, and so on until you got to the last bulb. That bulbs negative terminal went to the wall outlets negative terminal. Series wiring of speakers is basically the same. If one speaker dies, they all quit playing. The resistance is additive. Three 4 ohm speakers add up to a 12 ohm load.
Parallel wiring has a seperate positive and negative lead going from the amp output to each speaker input. The resistance R is 1/(1/R1 + 1/R2 + 1/R3 + ...1/Rn)
Remember the old Christmas tree lights? When one bulb burnt out the whole string of lights would turn off. They were wired in series. A positive came from the wall outlet to the first bulb, from that negative terminal it ran to the next bulbs positive, from that bulbs negative to the next bulbs positive, and so on until you got to the last bulb. That bulbs negative terminal went to the wall outlets negative terminal. Series wiring of speakers is basically the same. If one speaker dies, they all quit playing. The resistance is additive. Three 4 ohm speakers add up to a 12 ohm load.
Parallel wiring has a seperate positive and negative lead going from the amp output to each speaker input. The resistance R is 1/(1/R1 + 1/R2 + 1/R3 + ...1/Rn)
08-27-2001, 08:35 AM
#4
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Yes, it is wrong. First of all is yor amp stable at 2 ohms bridged? You say in the original post that it puts out 150 x 2 at two ohms stereo. When you bridge to 2 ohms and then bridge the amps channels the amp sees it the same as 1 ohm stereo.
Secondly the amp should only have one pair of wires connected to it's individual pair of bridged outputs ~ the bridged amp will use one output from each pair of channels, I don't know which pair because it varies from one amp to the next. That pair of wires, one positive and one negative, will go to one speaker, from that speaker to the next. This is for parallel wiring. Series wiring would be as I said in previous post. Series would give the amp a 4 ohms stereo, 8 ohms bridged load, the same as if you just hooked up in stereo. This may be the only alternative if you have an average amp that is only stable to 2 ohms stereo, 4 ohms bridged.
Secondly the amp should only have one pair of wires connected to it's individual pair of bridged outputs ~ the bridged amp will use one output from each pair of channels, I don't know which pair because it varies from one amp to the next. That pair of wires, one positive and one negative, will go to one speaker, from that speaker to the next. This is for parallel wiring. Series wiring would be as I said in previous post. Series would give the amp a 4 ohms stereo, 8 ohms bridged load, the same as if you just hooked up in stereo. This may be the only alternative if you have an average amp that is only stable to 2 ohms stereo, 4 ohms bridged.
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