volumetric efficiency estimate
#1
volumetric efficiency estimate
How do you estimate the volumetric efficiency of a boosted car?
I have seen one approach where you just use the pressure ratio as the volumetric efficiency, which seems a bit optimistic.
Maybe a more realistic estimate is NA volumetric efficiency times pressure ratio?
I have seen one approach where you just use the pressure ratio as the volumetric efficiency, which seems a bit optimistic.
Maybe a more realistic estimate is NA volumetric efficiency times pressure ratio?
#3
Originally posted by MardiGrasMax
With boost I thought it was 100%
With boost I thought it was 100%
For instance, if you wanted to calculate air flow into the engine. I have seen an equation for a supercharged engine where the effective volumetric efficiency was just the pressure ratio produced by the blower. So for instance, if you are running 9 psi at 6500 rpm:
PR = (14.7 + 9)/14.7 = 1.61
so: cfm = (183 x 6500 x 1.61 x .5)/ 1728 = 554 cfm
where:
183 = engine displacement in cubic engines
6500 = engine rpm
.5 = number of intake strokes per engine revolution
1728 = conversion from cubic inches to cubic feet
But using the pressure ratio for the effective volumetric efficiency seems a tad optimistic to me.
#4
Originally posted by Stephen Max
I guess I'm thinking of an effective volumetric efficiency that includes the effect of the supercharger.
For instance, if you wanted to calculate air flow into the engine. I have seen an equation for a supercharged engine where the effective volumetric efficiency was just the pressure ratio produced by the blower. So for instance, if you are running 9 psi at 6500 rpm:
PR = (14.7 + 9)/14.7 = 1.61
so: cfm = (183 x 6500 x 1.61 x .5)/ 1728 = 554 cfm
where:
183 = engine displacement in cubic engines
6500 = engine rpm
.5 = number of intake strokes per engine revolution
1728 = conversion from cubic inches to cubic feet
But using the pressure ratio for the effective volumetric efficiency seems a tad optimistic to me.
I guess I'm thinking of an effective volumetric efficiency that includes the effect of the supercharger.
For instance, if you wanted to calculate air flow into the engine. I have seen an equation for a supercharged engine where the effective volumetric efficiency was just the pressure ratio produced by the blower. So for instance, if you are running 9 psi at 6500 rpm:
PR = (14.7 + 9)/14.7 = 1.61
so: cfm = (183 x 6500 x 1.61 x .5)/ 1728 = 554 cfm
where:
183 = engine displacement in cubic engines
6500 = engine rpm
.5 = number of intake strokes per engine revolution
1728 = conversion from cubic inches to cubic feet
But using the pressure ratio for the effective volumetric efficiency seems a tad optimistic to me.
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