What's the formula for HP savings with every lb taken off our car?

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Aug 12, 2001 | 11:43 AM
  #1  
I know there's a formula to calculate HP saved / freed up by making out car lighter ... which is why people use a lighter flywheel or UDP or carbon fibre hood!

but what is it?

I'm contemplating the carbon fiber hood ... 25 lb savings ... is that really a big deal? I could just go on a diet!
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Aug 12, 2001 | 03:01 PM
  #2  
I suspect the formula that you are looking for is the one which shows the effect on ET of a change in HP or weight. You can play with it mathematically by holding the ET constant and watching the effect on HP of the weight reduction

The relationship between HP, weight and ET is as follows;

HP = (weight)/(ET/5.825)^3 ......that would be to the third power or cubed on the last term

As an example if one were to ask the question how much HP would it take to propel a 3440 lb car to a 14.05 ET, the above equation would net 245HP.

BTW, all of that has nothing to do with why people lighten flywheels. That has to do with overcoming rotating inertia and is a whole different phenomenon.
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Aug 12, 2001 | 03:07 PM
  #3  
hmmm ... wow ... more info than I was expecting but that's gr8! I was looking 4 the more gen'l formula ... like 1 lb = 2 hp savings etc ...

Quote:
Originally posted by Gerry
I suspect the formula that you are looking for is the one which shows the effect on ET of a change in HP or weight. You can play with it mathematically by holding the ET constant and watching the effect on HP of the weight reduction

The relationship between HP, weight and ET is as follows;

HP = (weight)/(ET/5.825)^3 ......that would be to the third power or cubed on the last term

As an example if one were to ask the question how much HP would it take to propel a 3440 lb car to a 14.05 ET, the above equation would net 245HP.

BTW, all of that has nothing to do with why people lighten flywheels. That has to do with overcoming rotating inertia and is a whole different phenomenon.
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Aug 12, 2001 | 03:08 PM
  #4  
I've been told that for all intents and purposes, lightening your car by 100lbs. will shave .1 second off a 1/4 mile run. Now, losing 25 lbs off the front end will help to brign your car into better 50/50 weight balance and give it more neutral handling...
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Aug 12, 2001 | 03:10 PM
  #5  
Hey Bud,

Is that a new ride? I thought u had a 3rd or 4th gen?

Quote:
Originally posted by Ironlord
I've been told that for all intents and purposes, lightening your car by 100lbs. will shave .1 second off a 1/4 mile run. Now, losing 25 lbs off the front end will help to brign your car into better 50/50 weight balance and give it more neutral handling...
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Aug 12, 2001 | 03:15 PM
  #6  
Quote:
Originally posted by ohboiya
Hey Bud,

Is that a new ride? I thought u had a 3rd or 4th gen?

nope, got some new pics. had an old grand prix and got this 2k1 in july...
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Aug 12, 2001 | 03:15 PM
  #7  
Generalizations are not linear, which is why there is a cubed term in the formula, but if you knock 25 lbs off the example above, the HP changes by about 1.5
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Aug 12, 2001 | 03:24 PM
  #8  
Quote:
Originally posted by Gerry
Generalizations are not linear, which is why there is a cubed term in the formula, but if you knock 25 lbs off the example above, the HP changes by about 1.5
that's f&cking it? I get a 1.5 hp savings for buying a $450 carbon fiber hood?
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Aug 12, 2001 | 03:34 PM
  #9  
Quote:
Originally posted by ohboiya


that's f&cking it? I get a 1.5 hp savings for buying a $450 carbon fiber hood?
No, you don't get 1.5 hp for lightenign by 25 lbs, you free up 1.5 hp. It means you need 1.5 hp less to run the exact same time. So you can probably expect like .02 saved on a 1/4. But it really will help your weight distribution.

And gerry, i know its not perfect, but everything i've been told is that its pretty d*mn good and really close to reality...
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Aug 12, 2001 | 03:42 PM
  #10  
Yes, I realize the 0.1 sec per hundred lbs is a pretty good estimate. I was just trying to address his original question where he asked about a formula relating weight to HP. Being an Engineering nerd, I couldn't help but cough up the proper math. Its a personal weakness........
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Aug 12, 2001 | 03:56 PM
  #11  
Quote:
Originally posted by Gerry
Yes, I realize the 0.1 sec per hundred lbs is a pretty good estimate. I was just trying to address his original question where he asked about a formula relating weight to HP. Being an Engineering nerd, I couldn't help but cough up the proper math. Its a personal weakness........
Ah, its ok, no harm, all in good fun. And actually, that formula should help me, i'm databasing and referncing all the data and times and what not for all my track times, maybe help figure what works and what doesn't...

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Aug 12, 2001 | 04:25 PM
  #12  
Quote:
Originally posted by Ironlord
I've been told that for all intents and purposes, lightening your car by 100lbs. will shave .1 second off a 1/4 mile run.
I thought that saying was true for those really powerful rear-wheel drive muscle cars. For our FWD cars, it may not hold true....
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Aug 12, 2001 | 04:58 PM
  #13  
Actually for our relatively lighter cars, the improvement for a 100 lb reduction is slightly higher, about 0.12 sec per 100 lbs per the formula above with a 3200# car of about 200 hp.
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Aug 12, 2001 | 05:12 PM
  #14  
are these actually accurate? theres a lot of things that take place in using that ET forumla. Auto/Manual is one variable, How tall/short the gearings are, the power band of the engine, BLAH BLAH. so how can you guys assume that this many lbs will take off this much on your ET? and you have to put into consideration of your Rims too... someone correct me if im going onto my little world of mine.
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Aug 12, 2001 | 05:31 PM
  #15  
The relations are correct from a perspective of basic physics, and are just variations of the basic equations of mass and acceleration. They are from the "Auto Math Handbook" which is a well regarded reference by most serious car folks. In fact, that is the same basic equation that is going on inside a g-tech pro or similar device.

You are quite correct that there are other variables which will have effects and muddy the waters. But the equation is generally accurate for the case in question, where you are making one change (ie. weight) to a given car. They would be much less reliable if used to compare, say et's for two very different designs. It is certainly more accurate than most of the "general rules of thumb". Its not perfect, but useful.
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Aug 12, 2001 | 09:40 PM
  #16  
Hmmm... maybe its time to lose hmmm... say ~75lbs... off my gut! maybe i can shift faster too!
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Aug 13, 2001 | 09:09 AM
  #17  
I've heard the forumla is 7lbs = 1hp. Read that a while ago but I have no idea where it came from.
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Aug 13, 2001 | 10:27 AM
  #18  
Quote:
Originally posted by Gerry
I suspect the formula that you are looking for is the one which shows the effect on ET of a change in HP or weight. You can play with it mathematically by holding the ET constant and watching the effect on HP of the weight reduction. . . .
For correlating weight drop to equivalent power it's probably better to use the equation for 1/4 mile mph instead of the one for ET, since mph is more closely a function of hp (ET is also much more sensitive to traction and starting line technique). These formulas are actually curve fits made to a lot of data (most commonly linked to the efforts of some Mopar engineers during the mid/late 60's). They're pretty good, but still approximations.

I've used the following formula for estimating 1/4 mile mph

mph = 225 * (hp/weight)^(1/3) (Formula 1)

Solving for hp required as a function of weight gives the following:

hp = weight * (mph/225)^3 (Formula 2)

So removing 25 lbs from a 245 HP car that originally weighs 3440 lbs (predicted to run 97.12 mph in the 1/4 using Formula 1) is about the same as increasing the HP by 1.7 or so. Or with the same HP, a trap speed of 97.34 mph instead of 97.12 mph. [edited for consistency]

One of the magazines published both of these formulas recently, and I think they used a number slightly different from my 225 in the one for trap speed, which might change the equivalent HP by a tenth or so. Like what's been said, it's approximate.

Norm
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